# Line slope calculator 8x+y=48

**Straight line given by points A[5; 8] and B[6; 0]**

## Calculation:

**Slope-intercept form of line:**y = -8x+48

**Canonical form of the line equation:**8x+y-48 = 0

**Parametric form of the line equation:**

x = t+5

y = -8t+8 ; t ∈ R

**Slope:**m = -8

**Slope angle of line: φ =**-82°52'30″ = -1.4464 rad

**X intercept:**x

_{0}= 6

**Y intercept:**y

_{0}= q = 48

**Distance line from the origin:**d

_{0}= 5.9537

**The length of the segment AB: |AB| =**8.0623

**Vector: AB =**(1; -8)

**Normal vector: n =**(8; 1)

**Midpoint of the segment AB: M =**[5.5; 4]

**Perpendicular Bisector equation:**x-8y+26.5 = 0

**Vector OA = (5; 8) ; |OA| = 9.434**

**Vector OB = (6; 0) ; |OB| = 6**

**Scalar product OA .OB = 30**

**Angle ∠ AOB = 57°59'41″ = 1.0122 rad**